Subplot in matlab9/25/2023 'type', 'scatter' ) data = layout = struct (. Instead, I had to make the axes children of the new figure.Trace1 = struct (. 9 jupyter notebooks kernel keeps dying when I run the code. Object figure can not be a child of parent Jupyter (GitHub: jupyter-matlab-proxy) was released a few months ago. For example hNew = copyobj(fig(1),hFigure) gave the error Error using copyobj It seemed that a figure couldn't be made the child of another figure. The code from gnovice didn't work for me. You could avoid the need to create and then delete subplots by specifying the positions yourself. Set(hNew,'Position',newPos) %# Modify its positionĪlso note that SUBPLOT is only used here to generate a position for the tiling of the axes. E Calculating the output voltage in Discontinuous conduction 146 Matlab. If you want the axes object to appear in both figures, you can instead use the function COPYOBJ like so: hNew = copyobj(fig(1),hFigure) %# Copy fig(1) to hFigure, making a new handle subplot('Position',0.10 0.15 0.80 0.35) plot(t,y(:,2),'b') grid on hold. The above will actually move the axes from the old figure to the new figure. In your case, several of the positions are overlapping. As it states in the manual, if it overlap, it will erase the graph that is under. subplot ('Position', left bottom width height) And this is where you have a problem. HTemp = subplot(2,1,2,'Parent',hFigure) %# Make a new temporary subplot subplot (m,n,p) Which uses the m x n grid plotting in the p position. Set(fig(1),'Parent',hFigure,'Position',newPos) %# Move axes to the new figure NewPos = get(hTemp,'Position') %# Get its position HTemp = subplot(2,1,1,'Parent',hFigure) %# Create a temporary subplot You can use the title, xlabel, and ylabel commands directly with tiledlayouts: Alternatively, starting in R2018b, the sgtitle function will add a title over a group of subplots. However, to answer the question you asked, here's a way to accomplish this given that you are outputting the axes handles (not the figure handles) in the vector fig ( note: this is basically the same solution as the one given in the other question, but since you mention having trouble adapting it I thought I'd reformat it to better fit your specific situation): hFigure = figure() %# Create a new figure Starting in R2019b, you can also use tiledlayout and nexttile instead of subplot, which has shared titles and labels. no additional arguments specified) would be to create its own figure and place the plot there. The default behavior of myFunkyFigure (i.e. Of course, if there's no need to only set the figure's color at the end of the loop, you can. subplot( m, n, p ) divides the current figure into an m -by- n grid and creates axes in the position specified by p. You can then use fh to change the figure's properties, e.g. fh figure creates a new figure and captures the figure handle in the variable fh. MyFunkyFigure(dataSet2,hSub2) %# Add a funky plot to the second subplot axes To create a new figure, you do not have to call figure with an argument. HSub2 = subplot(2,1,2) %# Create a second subplot MyFunkyFigure(dataSet1,hSub1) %# Add a funky plot to the subplot axes Then you would use it like so: hSub1 = subplot(2,1,1) %# Create a subplot Obviously, we don't know how "funky" your figures are, but it should be noted in such a case that the cleanest solution would be to modify the function myFunkyFigure such that it accepts additional optional arguments, specifically the handle of an axes in which to place the plot it creates.
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